I am working on a program that contains a canvas, but I want the canvas to save as a .jpg file instead of a data:image/jpeg dfkasd;flaehfoewhfer. The goal is for the user to drag the position of one .png file above another and then that will be translated to a canvas, which will then save itself as a .jpg file so that I can put it into my MySQL database. Is there a way to do that? Here is what I have for my JavaScript:
function translateTo() {
var c = document.getElementById("myCanvas");
var ctx = c.getContext("2d");
var watermark = document.getElementById("watermark");
watermark.style.opacity = "0.3";
var top = document.getElementById("show-wm").offsetTop;
var right = document.getElementById("show-wm").offsetLeft;
var width = document.getElementById("show-wm").width;
var height = document.getElementById("show-wm").height;
ctx.globalAlpha = 0.4;
ctx.drawImage(watermark, right, top, width, height);
document.getElementById("url").value = c.toDataURL("image/jpeg", 1.0);
document.getElementById("watermark-form").submit();
}
HTML:
<form action="" method="post" id="watermark-form">
<input type="hidden" name="image" value="<?php echo $photo_id; ?>">
<input type="hidden" name="url" value="" id="url">
<input type="hidden" name="oldpath" value="<?php echo $photo_url; ?>">
</form>
<div class="draggable">
<img id="show-photo" src="https://theexplorerblog.com/images/<?php echo $img; ?>">
<img id="show-wm" width="220px" src="wide-logo.png" alt="Your Photo">
<a class="button" href="javascript:translateTo()">Finish</a>
</div>
<div class="hi">
<img id="photo" src="https://theexplorerblog.com/images/<?php echo $img; ?>">
<img id="watermark" width="220px" src="wide-logo.png" alt="Watermark">
</div>
<canvas id="myCanvas" style="border:1px solid #d3d3d3;">
Your browser does not support the HTML5 canvas tag, so we are unable to make your watermarked photo.
</canvas>
and PHP for the form(I defined connection earlier):
<?php
if(isset($_POST['url'])){
$image_id = mysqli_real_escape_string($connection,$_POST['image']);
$url = $_POST['url'];
$photourl = mysqli_real_escape_string($connection,$_POST['oldpath']);
$query = "UPDATE photos SET photo_url='$url',photo_no_wm='$photourl' WHERE id='$image_id'";
$result = mysqli_query($connection,$query);
if($result){
header("location: submitphoto.php?wm=true");
}
}
?>
When I run this, it makes it into a data:image/jpeg file which is tooooooo long. I would like to make it a short .jpg name.
Aucun commentaire:
Enregistrer un commentaire