I want to make 2 charts, it is "gender chart" and "fakultas chart", but when I try to code like this, just one chart that appeared, what should I do so that all chart will be appearing?
my code is like this
JAVASCRIPT CODE
$(document).ready(function(){
$.ajax({
url: "http://localhost/chartjs/data.php",
method: "GET",
success: function(data) {
console.log(data);
var Gender = [];
var jumlah = [];
var Fakultas = [];
var jumlah_orang = [];
for(var i in data)
{
//Gender.push("Gender " + data[i].JenisKelaminID);
if(data[i].JenisKelaminID == 1)
{
Gender.push("Men");
}
else if(data[i].JenisKelaminID == 2)
{
Gender.push("Women");
}
else
{
Gender.push("Other");
}
jumlah.push(data[i].jumlah);
Fakultas.push(data[i].Fakultas);
jumlah_orang.push(data[i].jumlah_orang);
}
var chartdata = {
labels: Gender,
datasets: [
{
label : 'Total',
backgroundColor: [
'rgba(79, 181, 59, 1)', //green for men
'rgba(239, 87, 196, 1)', //pink for women
'rgba(166, 160, 164, 1)', //grey for other
],
borderColor: 'rgba(200, 200, 200, 0.75)',
hoverBackgroundColor: 'rgba(200, 200, 200, 1)',
hoverBorderColor: 'rgba(200, 200, 200, 1)',
data: jumlah
}
]
};
var chartdata2 = {
labels: Fakultas,
datasets: [
{
label : 'Total',
backgroundColor: [
'rgba(79, 181, 59, 1)',
'rgba(239, 87, 196, 1)',
'rgba(166, 160, 164, 1)',
'rgba(16, 60, 64, 1)',
'rgba(66, 16, 164, 1)',
'rgba(77, 18, 74, 1)',
'rgba(6, 60, 64, 1)',
'rgba(86, 10, 64, 1)',
],
borderColor: 'rgba(200, 200, 200, 0.75)',
hoverBackgroundColor: 'rgba(200, 200, 200, 1)',
hoverBorderColor: 'rgba(200, 200, 200, 1)',
data: jumlah
}
]
};
var ctx = $("#mycanvas");
var ctx2 = $("mycanvas2")
var barGraph = new Chart(ctx, {
type: 'bar',
data: chartdata
});
var barGraph2 = new Chart(ctx2, {
type: 'bar',
data: chartdata2
});
},
error: function(data) {
console.log(data);
}
});
});
MY PHP CODE
<?php
//setting header to json
header('Content-Type: application/json');
//database
define('DB_HOST', '127.0.0.1');
define('DB_USERNAME', 'root');
define('DB_PASSWORD', '');
define('DB_NAME', 'dbintegrasi');
//get connection
$mysqli = new mysqli(DB_HOST, DB_USERNAME, DB_PASSWORD, DB_NAME);
if(!$mysqli){
die("Connection failed: " . $mysqli->error);
}
//query to get data from the table
$query = sprintf("SELECT JenisKelaminID, COUNT(JenisKelaminID) as jumlah FROM tahunmasukmagister GROUP BY JenisKelaminID");
$query2 = sprintf("SELECT FAKULTAS, COUNT(FAKULTAS) as jumlah_orang FROM s2view GROUP BY FAKULTAS");
//execute query
$result = $mysqli->query($query);
$result2 = $mysqli->query($query2);
//loop through the returned data
$data = array();
foreach ($result as $row){
$data[] = $row;
}
foreach ($result2 as $row){
$data[] = $row;
}
//freee memory associated with result
$result->close();
$result2->close();
//close connection
$mysqli->close();
//new print the data
print json_encode($data);
MY HTML CODE
<!DOCTYPE html>
<html>
<head>
<title>Chart JS Graph Examples</title>
<!-- Bootstrsap -->
<link href="vendors/bootstrap/dist/css/bootstrap.min.css" rel="stylesheet">
</head>
<!-- <head>
<title>ChartJS - BarGraph</title>
<style type="text/css">
#chart-container {
width: 640px;
height: auto;
}
</style>
</head> -->
<body>
<div class="container body">
<div class="col-md-6 left_col">
<div class="left_col scroll-view">
<a href="index.html" class="site_title"><span>Pascasarjana Dalam Angka IPB</span></a>
</div>
<div class="clearfix"></div>
<div id="chart-container">
<br><br>
<a class="site_title"><span>Bar Chart</span></a>
<canvas id="mycanvas"></canvas>
</div>
<div id="chart-container2">
<canvas id="mycanvas2"></canvas>
</div>
<!-- javascript -->
<script type="text/javascript" src="js/jquery.min.js"></script>
<script type="text/javascript" src="js/Chart.min.js"></script>
<script type="text/javascript" src="js/app.js"></script>
</body>
</html>
please help me to solve that problem. thankyou
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