This works fine:
fetch("./xml/Stories.xml").then((response) => {
response.text().then((xml) => {
xmlContent = xml;
But I would like to get my data from a website which has a link that only displays the xml, how would I go about retrieving the data through a link instead of a direct file path?
I.E:
fetch("https://Example.com/").then((response) => {
response.text().then((xml) => {
xmlContent = xml;
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