dimanche 7 janvier 2018

Always same value for id in controller

guys. I use Asp.net MVC and C#. I have 2 buttons for every object on page. First button for add in shop cart, second button for view details. So this buttons generate for every object in my model. I want to pass id field into controller, but i always got id = 1 in action. How i can pass the right id? Can someone explain ?

Here is form:

@model IEnumerable<StickerOn.Models.Sticker>
@{
    ViewBag.Title = "Index";
    Layout = "~/Views/Shared/_Layout.cshtml";
}
@using (Html.BeginForm("RedirectButton", "Sticker", FormMethod.Post))
{
    <div style="margin-left:50px">
        <div class="body-content">
            @for (int i = 0; i < Model.Count() - 1; i++)
            {
                <div class="row">
                    @foreach (var item in Model)
                    {
                        <div class="col-md-4">
                            <div class="thumbnail">
                                <img src="@item.ImgToReprs" alt="..." width="200" height="100">
                                <div class="caption">
                                    <h3>@item.Name</h3>
                                    @Html.DisplayFor(m => item.id)
                                    <input type="hidden" name="id" value="@item.id" />
                                    <p><button type="submit" id="@item.id" name="submitButton" class="btn btn-success"><i class="glyphicon glyphicon-shopping-cart"></i></button><input type="submit" name="submitButton" class="btn btn-default" value="..." /></p>
                                </div>
                            </div>
                        </div>
                    }
                </div>
            }
        </div>
    </div>
}

And my controller:

[HttpPost]
public ActionResult RedirectButton(int? id,string submitButton)
        {
            var g = Request.Form["id"];
            switch(submitButton)
            {
                case "...":
                    return Details(1);
                case "":
                    break;
            }
            return View();
        }

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