I have to make a web service. Therefore I referred some tutorials in the internet and came up with the following codes
index.php
<html>
<head>
<title>Form page</title>
</head>
<body>
<form action="http://localhost:81/my%20web%20service/webservice" method="get">
Table name:<br>
<input type="text" name="s" value=""><br>
<input type="submit" value="Submit">
</form>
</body>
</html>
webservice.php
<?php
include('connectdb.php');
$something = $_GET['s'];
$sqlcode = mysql_query("Select * from $something");
$jsonObj= array();
while($result=mysql_fetch_object($sqlcode))
{
$jsonObj[] = $result;
}
$final_res =json_encode($jsonObj) ;
echo $final_res;
?>
connectdb.php
<?php
$hostname="localhost";
$username="root"; //write your username
$password=""; //write your password
$db_name="webservice_trial"; //write your db name
$con=mysql_connect($hostname,$username,$password);
mysql_select_db($db_name,$con) or die ("Cannot connect the Database");
mysql_query("SET NAMES 'utf8'",$con);
?>
The above codes works fine. When I enter a name of a table from form.php, it will retrieve all tuples in that particular table.
Now what I want to do is to make data display on another page. i.e. I want to transfer data from webservice.php to another page from json format. so I edited my webservice.php as following
webservice.php
<?php
include('connectdb.php');
$something = $_GET['s'];
$sqlcode = mysql_query("Select * from $something");
$jsonObj= array();
while($result=mysql_fetch_object($sqlcode))
{
$jsonObj[] = $result;
}
$final_res =json_encode($jsonObj) ;
echo $final_res;
$jsonArray = (array) json_decode($final_res);
echo jsonArray[0];
?>
it gives the following error
Parse error: syntax error, unexpected '[', expecting ',' or ';' in C:\xampp\htdocs\json_folder\my web service\webservice.php on line 18
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